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题目内容
xy+y < 0

Quantity A

x

Quantity B

y

Quantity A

$$(2m+1)^{2}$$

Quantity B

$$(2(m+1))^{2}$$
$$x^{2}$$-$$y^{2}$$=-10

Quantity A

x+y

Quantity B

x-y
x is a negative integer

Quantity A

$$(2^x)^2$$

Quantity B

$$(x^2)^x$$
n is a positive integer

Quantity A: $$(\frac{1}{2})^{n}$$

Quantity B: (3)·$$(\frac{1}{10})^{n}$$

Quantity A

$$\frac{x}{(x+1)}$$

Quantity B

1
$$x \gt 0$$

$$y \gt 0$$

Quantity A

($$\sqrt{x}$$)($$\sqrt{y}$$)

Quantity B

$$\sqrt{x+y}$$
$$p$$, $$s$$, and $$t$$ are probabilities and $$0 \lt p \lt s \lt t$$.

Quantity A

$$p+st$$

Quantity B

$$s(p+t)$$
If n=$$2^{3}$$, then$$n^{n}$$=
s and t are positive integers, and $$32^{s}$$=$$2^{t}$$.

Quantity A

s:t

Quantity B

0.2
$$x \geq 0$$

Quantity A

$$2^{x}$$+$$2^{x}$$+$$2^{x}$$+$$2^{x}$$

Quantity B

$$4^{x}$$+$$4^{x}$$
If a, b, x, and y are positive integers, and $$13^{a}$$*$$13^{b}$$=($$13^{x})^{y}$$=$$13^{13}$$, what is the average (arithmetic mean) of a, b, x, and y?

Give your answer as a decimal.
Which of the following is/are equal to $$\frac{1}{560}^{-4}$$?

Indicate all correct answers.
$$a_1$$=1, $$a_2$$=1, $$a_n$$=0.2$$a_{n-1}$$(n ≥ 3)

Quantity A: $$a_6$$

Quantity B: $$25^{3}$$$$0.2^{10}$$
Which of the following is equal to (6)($$14^{8}$$)+(15)($$14^{7}$$)?
List D: $$(-\frac{1}{2})^{2}$$, $$(-\frac{1}{2})^{-2}$$, $$(-\frac{1}{3})^{2}$$, $$(-\frac{1}{3})^{-2}$$

What is the range of the numbers in list D?
$$x^{y}$$ > 0, x$$y^{2}$$ < 0

Quantity A

x

Quantity B

y
x is an integer greater than 1.

Quantity A

$$3^{x+1}$$

Quantity B

$$4^{x}$$
0 < a< b < 1 < c < d, c and d are both integers

Quantity A

$$a^{c-d}$$

Quantity B

$$b^{d-c}$$
The product of 702,368 and 96,638 lies between?

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