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全部 图表题专项练习 分难度套题练习 GRE数学6000题170逐考点专项练习 GRE数学170超高频“脏”题 GRE数学170超高频“坑”题 GRE数学170超高频“神”题
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题目内容
1 < 2x+1 < 3

Quantity A

($$x^{2}$$-5)-(x-5)

Quantity B

0
R wins 101 more votes than T. If x votes are removed from R and given to T, then T will have more votes than R.

Quantity A

The least value of x

Quantity B

51
$$x \gt 0$$ and $$\frac{5}{27}x^{2}$$=$$x$$

Quantity A

$$x$$

Quantity B

$$5$$
$$x$$ and $$y$$ are positive integers

$$x^{2}$$+$$y^{2}$$=89

$$xy=40$$

Quantity A

|$$x-y$$|

Quantity B

$$3$$
xy = 2

If the average of x and y is 3, then $$x^{2}$$ + $$y^{2}$$ = ?
If $$(x+\frac{1}{x})^{2}$$=4, then $$x^{2}$$+$$(\frac{1}{x})^{2}$$= ?
x ≠ 0

$$(a+\frac{1}{a})^{2}$$=5

Quantity A

$$a^{2}$$+$$(\frac{1}{a})^{2}$$

Quantity B

3
x > 0, y > 0

Quantity A

x+y

Quantity B

$$\sqrt{x^{2}+y^{2}}$$
x > 0, y < 0

Quantity A:x+y-1

Quantity B:x-y+1
y+5 > x

Quantity A

y+2

Quantity B

x-2
x-y=1

Quantity A

$$x^{2}$$ - $$y^{2}$$

Quantity B

1
-1 ≤ x ≤ 1and -1 ≤ y ≤ 1

Quantity A

$$(x+y)^{2}$$

Quantity B

$$xy^{2}$$
x+y ≠ 0

Quantity A

$$2(x+y)^{2}$$

Quantity B

$$(2x+2y)^{2}$$
x > 0, y < 0

Quantity A:x+y-1

Quantity B:x-y+1

Quantity A

$$(x+\frac{1}{x})^{-3}$$

Quantity B

$$x^{-3}$$ + $$(\frac{1}{x})^{-3}$$
x-y > y

x-y < x

Quantity A: x

Quantity B: y

Quantity A

($$x^{2}$$ + $$y^{2}$$) ($$x^{2}$$ - $$y^{2}$$)

Quantity B

($$x^{3}$$+$$y^{3}$$) (x-y)
ab≠0

Quantity A

$$\sqrt{a^{2}+b^{2}}$$

Quantity B

$$\sqrt{a^{2}}$$ + $$\sqrt{b^{2}}$$
Among people A, B and C, B is 5 years older than A, while B is 20 years older than C.

Quantity A

A

Quantity B

2C
y > 1

Quantity A

100$$y^{2}$$

Quantity B

225($$y^{2}$$ - 1)

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25000 +道题目

6本备考书籍

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